Year 12

AQA A level Biology Enzymes Notes

Enzymes

— Biology · AS Level (7402) · Crash Course —
★ Exam Tip: Graph questions on enzymes come in pairs — “Describe” (2 marks: only what you can SEE) and “Explain” (3–4 marks: the WHY). The mark schemes are different, so never mix them up! Past-paper practice follows this chapter.

1. What are Enzymes?

Definition:An enzyme is a protein produced by a living organism that acts as a biological catalyst in a chemical reaction by reducing EA (activation energy).
  • Biological catalyst = speeds up a reaction but remains unchanged at the end of it.
  • Lowers the activation energy required by providing an alternate pathway.
  • All enzymes are globular proteins with a tertiary structure (3rd level of folding ⇒ 3D shape).
  • Almost all metabolic reactions in living organisms are catalysed by enzymes ⇒ enzymes are essential for life.
Note: ALL enzymes have a tertiary structure; only those made of more than one polypeptide chain also have a quaternary structure.

Metabolism = sum of all chemical reactions going on in the body

Metabolism AnabolicCatabolicsynthesis of larger compoundsfrom smaller onesCONDENSATION (H₂O released)breakdown of larger compoundsinto smaller onesHYDROLYSIS (H₂O used)
two halves of metabolism: build-up (anabolic) vs break-down (catabolic)
Examples (enzyme named above the arrow):Catabolic: H₂O + maltose —maltase→ 2 α-glucose (monomers)
Anabolic: fructose + α-glucose —sucrase→ sucrose + H₂O

Intracellular vs Extracellular enzymes

All enzymes are produced within a cell, but not all work inside it — some are secreted outside.

CELLIntracellular enzymese.g. catalase, lysosomal enzymes(function WITHIN the cell) exitExtracellular enzymese.g. digestive enzymes(function OUTSIDE the cell)
secreted enzymes leave the cell and work outside it

2. Properties of Enzymes

  1. Globular proteins (soluble).
  2. All have a tertiary structure ⇒ that is why they have an active site.
  3. Sensitive to changes in external factors (e.g. temperature & pH) — because they are globular proteins.
  4. Specific (to their substrate) because of the unique & complementary shape of the active site.
  5. Efficient — a small amount of enzyme can catalyse a large number of reactions.
  6. Lower the activation energy of a reaction by providing an alternate pathway.
Sir's analogy: two workers, 9-to-5. One finishes 2 tasks, the other 5 ⇒ the 2nd is more efficient.

Why “efficient”? Enzymes remain unchanged. One substrate binds → leaves as product → the next one binds → … so one enzyme molecule handles many substrates.

Enzyme activity & the factors affecting it

Enzyme activity = how well the enzyme catalyses its metabolic reaction (= rate of reaction).

# Factor Notation / note
1 Temperature —
2 Amount / concentration of substrate [S]
3 pH power of H⁺
4 Amount / concentration of enzyme [E]
5 Concentration of inhibitor anything that holds back / halts the enzyme
6 Coenzymes / cofactors (own sub-topic — see §9)
Remember: square brackets round anything, e.g. [S], mean concentration.

3. Mode of Action of Enzymes

Two models: (1) Lock & Key hypothesis and (2) Induced Fit hypothesis — both say the substrate binds the enzyme's active site.

Because of the tertiary structure (protein folding) an enzyme has a 3D shape. The active site is a hollow depression in the enzyme with a specific shape where another molecule (the substrate) can bind.

Q (board): Which bonds give the active site its shape? Tertiary-structure bonds → ① hydrogen bonds ② hydrophobic interactions ③ ionic bonds ④ disulfide linkages. (Not peptide bonds — those only hold the amino-acid sequence. Don't use quaternary: not all enzymes have it.)

① Lock & Key Hypothesis

Shape of the enzyme's active site is complementary to the shape of the substrate molecule.
  • Substrate = KEY, fits perfectly in the complementary active site ⇒ enzyme (active site) = LOCK. MCQ trap: which is lock, which is key?
  • Held by weak hydrogen bonds ⇒ forms the enzyme–substrate (E–S) complex.
  • Enzyme catalyses by lowering the activation energy ⇒ enzyme–product complex ⇒ products leave the active site.
  • Like keys & locks: every key can’t open every lock ⇒ that is why enzymes are specific. (Old idea, 1800s.)
Enzyme + Substrate E–S complex catalysis E–P complex Enzyme + Productssubstrate = KEY
lock & key: rigid active site, substrate fits exactly; enzyme comes out UNCHANGED

② Induced Fit Hypothesis

Shape of the active site is NOT complementary to the substrate. The active site moulds itself around the substrate to give a better fit.
  • Change in the active site shape = conformational change — induced by the substrate (the enzyme is “forced” to adjust).
  • Held by weak hydrogen bonds ⇒ E–S complex ⇒ catalysis by lowering EA ⇒ products leave, enzyme unchanged.
Sir's trick: buy a dress that almost fits ⇒ you alter the dress until it is tailored. Or clay moulded around an object.

Dates (sir's recollection): lock & key came first (1800s); induced fit later (~1949). Induced fit is why a slightly changed active site can still bind the substrate.

substrate shape ≠ active site conformational change site remoulds E–S complex E + products
induced fit: active site changes shape to wrap the substrate, then returns to normal
Lock & Key Induced Fit
Active site vs substrate complementary (exact) NOT complementary at first
Active site rigid moulds around substrate
Common to both weak H-bonds hold E–S complex · EA lowered via alternate pathway · enzyme unchanged at end

4. Activation Energy & How Enzymes Lower It

Activation energy (EA):the minimum amount of energy required to initiate a reaction.
  • Frequency of collisions = number of collisions per unit time.
  • Frequency of EFFECTIVE collisions ★ = collisions that result in a chemical reaction (product formation).
A B collide CEFFECTIVE(product formed)
only collisions that give a product (A + B → C) are “effective”

Why do we give heat? Heat is given as EA so reactant molecules gain kinetic energy, come close to one another and collide effectively & frequently.

reactantsproductsenergyEA without enzymeEA with enzyme
enzyme (red path) = lower activation-energy hill ⇒ faster reaction
How does the enzyme lower EA? By bringing the substrate molecules closer, in a proper orientation, within the active site.

Bound in the active site, substrates are aligned ⇒ effective collisions are much more likely ⇒ an alternate pathway with lower EA ⇒ a relatively faster reaction (less energy and less time needed).

Forming products: the substrate sitting in the active site is put under strain (pressure) ⇒ it breaks off into products.

5. Affinity, Vmax and Km

Affinity:a measure of the strength of attraction between the enzyme and the substrate.
  • Greater affinity for substrate ⇒ faster enzymatic activity.
  • Higher affinity ⇒ more likely that product will form in the presence of substrate.

Vmax = rate of reaction at which the enzyme shows its highest turnover. Turnover value = rate at which an enzyme converts its substrate into products. (Max rate / max velocity of the reaction.)

Vmax= 50Vmax/2= 25Km[substrate]rate of reaction (velocity)plateau = Vmax
y = dependent variable (rate/velocity), x = independent variable ([S]); Km = [S] at ½Vmax
Km (Michaelis–Menten constant):the substrate concentration at ½Vmax (Vmax/2).
  • Look at the substrate amount at ½Vmax — that [S] is Km.
  • Km is used as a measure of the efficiency AND affinity of an enzyme for its substrate.
LOWER Km ⇒ higher affinity ⇒ greater efficiency & activity
HIGHER Km ⇒ lower affinity
A B70355025Km(B)=2Km(A)=10[substrate]B: LOW Km ⇒ HIGHER affinityA: HIGH Km ⇒ LOWER affinity
enzyme B reaches ½Vmax with far less substrate (Km 2 vs 10 units) ⇒ B has higher affinity; A simply has the higher Vmax
Board check: Vmax(A) = 70, so ½Vmax = 35 (the board marks 30 on A's curve — a small slip; Km is read at 35, and it is still ≈ 10 units).
Enzyme AKm = 4 molecules of substrate≈ 4 molecules needed to reach ½Vmax
Enzyme BKm = 6 molecules of substrate≈ 6 molecules needed to reach ½Vmax

A has the lower Km (4 < 6) ⇒ A needs less substrate to get going ⇒ higher affinity / more efficient than B.

Link: Vmax is tied to how fast an enzyme recognises & binds its substrate (affinity), and can also be reached sooner by raising temperature (up to the optimum).

6. Factors Affecting the Rate of Enzyme Activity

★ DESCRIBE vs EXPLAIN (exam command words):
Describe (≈2 marks) = what you SEE in the graph — as if seeing it for the first time, no reasons. Explain (3–4 marks) = the WHY (reasons). Describe = “what”, Explain = “how/why”.
Trick: split the graph into part 1 and part 2 and describe, then explain, each part.

Always recall: enzymes = globular proteins ⇒ sensitive to changes in temperature & pH. Their 3D active-site shape is held by 4 tertiary bonds (H-bonds, hydrophobic, ionic, disulfide).

Axes rule: x-axis = independent variable (what you change), y-axis = dependent variable (rate of reaction). Temperature changes the rate — the reaction does not (noticeably) change the temperature.

① Temperature

Vmaxoptimum ≈ 40°C0102030506070≈0 at 61–62°C① rises② fallstemperature / °Crate of reaction
NOT symmetrical: gentle rise to the optimum, then a sharp fall to zero

Describe: ① As temperature increases, the rate of reaction increases until the optimum temperature (Vmax). ② Above the optimum temperature the rate of reaction decreases.

Explain:

  1. As temperature ↑ ⇒ kinetic energy ↑ ⇒ frequency of effective collisions ↑ ⇒ E–S complexes formed more frequently ⇒ rate of reaction ↑ until Vmax. (Same enzymes & substrates were already there — they just move/vibrate more and collide more.)
  2. Beyond the optimum: the enzyme / active site begins to lose its 3D (tertiary) structure because the hydrogen bonds, hydrophobic interactions and ionic bonds break down ⇒ specific shape of the active site lost ⇒ fewer E–S complexes ⇒ rate ↓.
Denaturation:losing its (3D) shape — the enzyme's “nature” — so the substrate no longer fits.
Say THREE bonds, not four! In denaturation name only H-bonds, hydrophobic interactions & ionic bonds. The disulfide bond (S–S between 2 cysteines) is very strong and does not break easily — never write that it breaks.
Why is the rate not 0 straight away at 41°C? The shape changes slowly; thanks to induced fit a slightly altered site still binds. Only around 61–62°C is it fully gone ⇒ rate 0.
normal sitedenatured(bonds broken)heat
substrate no longer complementary ⇒ E–S complex ↓

② pH (= power of H⁺)

optimum pHpHrate of enzyme activity
pH curve is usually SYMMETRICAL (bell-shaped)
Description: rate of reaction reaches Vmax at the optimum pH and declines at pH values other than optimum.

Explain: enzymes are sensitive to pH changes: they lose their tertiary structure at pH values other than optimum ⇒ fewer E–S complexes ⇒ the reaction recedes to zero.

Why? (changed R groups): pH tells the amount of H⁺ ions. Low pH = many H⁺; high pH (alkaline) = few. H⁺ is positive ⇒ it is attracted to negatively charged R groups and bonds with them ⇒ the normal tertiary bonding between R groups changes ⇒ specific 3D structure lost.

02468101214pepsin (pH ≈ 2)typical enzyme (opt. pH 8)catalase (pH ≈ 9)pH
each enzyme has ITS OWN, very specific optimum pH
pH is very specific: pepsin works in acid (pH ≈ 2), salivary amylase near neutral (pH 7 — not 8), catalase in alkaline conditions (pH ≈ 9). Temperature allows ~20° of slack either side of the optimum; for pH, a shift of just ~1 unit can drop the rate to zero.

③ Substrate concentration [S]

Vmax① [S] is thelimiting factor② [S] NOT limiting[substrate]rate of reaction
curve rises then plateaus at Vmax

Describe: ① Initially the rate of enzyme activity increases as [S] increases. ② At Vmax, increasing [S] is not affecting / not increasing the rate of reaction.

  1. Explain ①: at low [S], [S] is the limiting factor; increasing it ⇒ frequency of effective collisions ↑ ⇒ more E–S complexes.
  2. Explain ②: at a certain [S] activity reaches Vmax. All enzymes are saturated (all active sites occupied), so [E] is now the limiting factor ⇒ more [S] no longer ↑ the rate.
Sir's example:
10 molecules of amylase (starch → maltose) but no starch ⇒ no reaction. Eat potatoes (starch-rich) ⇒ [S] ↑ ⇒ rate ↑. Once all 10 active sites hold a substrate at the same instant, extra starch changes nothing — the enzymes can't work faster.

④ Enzyme concentration [E]

No enzyme ⇒ no catalysis, however much substrate there is. Two graphs exist:

Vmax① [E] limiting② [E] not limiting[enzyme]rate of reaction
FIXED [substrate] ⇒ curve + plateau
[E] ↑ AND [S] ↑[enzyme]rate of reaction
EXCEEDING [S] ⇒ straight line (rate ∝ [E])

Fixed [S] — Describe: ① ↑[E] increases the rate until Vmax is reached. ② Increasing [E] after Vmax has no effect — the rate stays constant (say “constant”, NOT “stops” — it doesn't fall to zero).

  1. Explain ①: at low [E], [E] is the limiting factor; ↑[E] ⇒ frequency of collisions ↑ ⇒ more E–S complexes formed.
  2. Explain ②: at a certain [E] the rate becomes constant and now [S] is the limiting factor (substrate used up — fixed amount at the start).
Exceeding [S] (both ↑ together): rate of rxn ∝ [E] and rate ∝ [S] ⇒ straight line, no plateau, because neither runs short.
Exam tip: the straight-line graph is usually NOT asked. The describe/explain graph you will see is the fixed-substrate curve. Limiting factor = the thing actually stopping the reaction going faster.

7. Enzyme Inhibitors

Certain chemicals selectively inhibit the action of specific enzymes — these chemicals are called enzyme inhibitors (they act as an obstacle / barrier that halts the enzyme).
Normal substrate binds ⇒ reaction Competitive ✗inhibitor fillsthe ACTIVE SITEsubstrate blocked out Non-competitive ✗inhibitor on ALLOSTERIC site⇒ active site distorted
competitive blocks the active site itself; non-competitive binds elsewhere (allosteric site) and distorts the active site
Competitive inhibitor Non-competitive inhibitor
Shape structurally similar to substrate (not identical) not similar to the substrate
Binds to the active site — competes with substrate for it the allosteric site — no competition for the active site
Effect substrate & inhibitor compete binding changes (conformational change) the active-site shape ⇒ substrate can't attach ⇒ no E–S complex
Reversible? Reversible: ↑[S] ⇒ substrate wins the site Usually called non-reversible: ↑[S] does not help (reverses only if the inhibitor detaches)
Km / affinity Km ↑ ⇒ affinity ↓ Km unchanged
Vmax remains the same decreases
Sir's trick: race analogy — 5 substrates vs 1 inhibitor: the odds favour the substrate if you add more of it, so the inhibition is defeated.

Why does Km ↑ (competitive)? The enzyme mistakes the inhibitor for the substrate, so its attraction (affinity) is divided between the two ⇒ affinity ↓ ⇒ more substrate is needed to reach ½Vmax ⇒ Km ↑. Vmax same because enough substrate can still push every active site to work.

Why Km same but Vmax ↓ (non-competitive)? Inhibitor and substrate share no similarity, so the enzyme's attraction to the substrate is not divided ⇒ affinity & Km unchanged. But enzymes with the inhibitor bound can never form E–S complexes, however much [S] ⇒ the maximum rate falls ⇒ Vmax ↓.

Km=3Km=5Normal enzymeCompetitive: Km ↑, same VmaxNon-competitive: Vmax ↓, Km same[substrate]rate of reaction
Km shifts right (3 → 5) with a competitive inhibitor; Vmax drops with a non-competitive one

Importance of enzyme inhibitors

  1. Antibiotics inhibit bacterial enzymes.
  2. They control the rate of metabolic reactions.
  3. Pesticides & herbicides contain inhibitors.

End-product inhibition (= feedback inhibition)

A metabolic pathway is a chain: products of enzyme A are the substrate of enzyme B, whose products are the substrate of enzyme C …

Enzyme A Enzyme B Enzyme C product 1product 2END PRODUCTsubstrate ↓ END PRODUCT binds allosteric site of enzyme A (negative feedback)A is switched OFF
when the end product is plentiful it inhibits the FIRST enzyme ⇒ whole pathway halts
  • The final product binds an allosteric site on the early-stage enzyme ⇒ its active-site shape changes ⇒ substrate 1 can no longer bind ⇒ entire metabolic pathway is halted (all later steps depend on the first).
  • Reduces the rate of the pathway; used to regulate a range of metabolic pathways.
  • An example of negative feedback — homeostatic control: stimulus = end product made in more than required ⇒ feedback shuts production off (like a barrier closing a full street).
  • Named “feedback” because the end product is giving a message back to the first enzyme: “stop — we don't need more”.

8. Immobilised Enzymes

Immobilised enzymes:enzymes that have been fixed to a surface or trapped inside beads of (agar / alginate) gel — attached to an inert, insoluble material.
  • Inert ⇒ does not take part in the E–S reaction. Insoluble ⇒ the enzyme does not dissolve and can be reused.
  • Free enzymes are soluble globular proteins and can move freely in the solution. Immobilising limits their mobility.
  • Methods exist (adsorption, covalent cross-linking, entrapment) — the syllabus method is entrapment in calcium alginate beads.

Using alginate to immobilise enzymes

  1. Mix the enzyme with sodium alginate solution and stir.
  2. Draw the mixture into a syringe; introduce it drop by drop into a beaker of CaCl2(aq).
  3. Ca²⁺ ions displace Na⁺ from the sodium alginate ⇒ gel-like, insoluble calcium alginate beads with the enzyme trapped inside.
  4. Rinse the beads with water before use.
sodium alginate + enzymemixed & stirred syringe drop by dropCaCl₂(aq): Ca²⁺ + Cl⁻Na⁺ displaced by Ca²⁺⇒ calcium alginatebeads (gel, insoluble)
sodium alginate + Ca²⁺ → calcium alginate (enzyme trapped inside each bead)

Advantages of immobilising enzymes

  1. Immobilised enzymes can be reused (they don't dissolve; beads are removed, rinsed, washed and used again).
  2. Saves the cost of extracting enzymes (from micro-organisms / animals) again and again — extraction is expensive & time-consuming.
  3. Enzymes become more stable (robust) to pH and temperature changes because it is harder to change their tertiary structure (protective inert coat).
  4. The enzyme does not contaminate the product and is easily separated from it.
  5. Immobilised enzymes have a larger shelf life.
  6. Higher yield.
30354045505560 free enzyme: optimum 45°Cimmobilised: optimum 50°Ctemperature / °Crelative activity (%)
immobilised (blue) peaks higher and falls more slowly ⇒ less sensitive to heat; free enzyme (red) denatures from 45°C (at 60°C: immobilised ≈ 28%, free ≈ 10%)

Real-life use: lactose-free milk

  • Lactose-intolerant people can't consume dairy (milk, cheese, yogurt) because it contains lactose.
  • Lactose is a disaccharide = glucose + galactose. The enzyme lactase hydrolyses lactose ⇒ milk becomes lactose-free.
Lactose —lactase (enzyme)→ glucose + galactose
milk (with lactose)column ofimmobilisedlactase beadslactose-free milklactose → glucose + galactose
milk runs through the bead column: lactose hydrolysed, lactase stays behind in the beads

Milk is allowed to run through a column of lactase-containing beads; the lactase hydrolyses the lactose to glucose & galactose. The collected milk contains no lactase — it is all trapped in the beads, which can be reused again and again.

Why not just mix lactase into the milk? It would be difficult to separate the lactase and get it back, and the milk would be contaminated with lactase enzyme.

9. Cofactors and Coenzymes

  • Coenzymes = organic molecules required for carrying out catalysis (usually vitamin derivatives).
  • Cofactors = inorganic materials, e.g. metals / metal ions.
  • Not every enzyme needs one — but some cannot work without their cofactor/coenzyme (their active-site shape is incomplete until it binds).
Apoenzyme(inactive protein)active site incomplete+ Cofactor /coenzyme(activator) Holoenzyme(active — substrate can bind)
cofactor / coenzyme binds ⇒ active site completed ⇒ enzyme activated
Enzyme Needs Type
Amylase Cl⁻ (chloride ion) cofactor
Carbonic anhydrase (in RBCs) Zn²⁺ (zinc ion) cofactor
(respiration / photosynthesis, A2) NAD — nicotinamide adenine dinucleotide coenzyme
(respiration / photosynthesis, A2) FAD — flavin adenine dinucleotide coenzyme

Cofactors & coenzymes matter again in A2 (respiration & photosynthesis); for AS, know the definitions and the apoenzyme → holoenzyme idea.

Quick Recap — Full Chapter Cheat-Sheet

✓ Enzymes at a glance
  • Enzyme = globular protein, biological catalyst, lowers EA (alternate pathway), unchanged at end; tertiary structure (quaternary only if >1 chain).
  • Lock & key: active site complementary (rigid). Induced fit: not complementary; site remoulds (conformational change). Both: weak H-bonds, E–S complex.
  • Enzyme lowers EA by bringing substrate closer, in proper orientation, in the active site.
  • Vmax = max rate (highest turnover). Km = [S] at ½Vmax; low Km = high affinity.
  • Temperature: ↑KE ⇒ ↑effective collisions ⇒ ↑E–S; above optimum H-bonds, hydrophobic & ionic bonds break ⇒ denatured (not disulfide!).
  • pH: symmetrical, very narrow optimum; H⁺ interacts with charged R groups ⇒ tertiary structure lost.
  • [S]: ↑rate until all active sites saturated, then [E] limiting. [E] (fixed [S]): ↑rate then [S] limiting.
  • Competitive: active site, reversible, Km ↑, Vmax same. Non-competitive: allosteric site, Vmax ↓, Km same.
  • End-product inhibition: last product inhibits first enzyme ⇒ pathway halts (negative feedback).
  • Immobilised (Ca-alginate beads): reuse, cheaper, more stable, no contamination, longer shelf life, higher yield. e.g. lactose-free milk.
  • Coenzyme = organic (vitamin derivative; NAD, FAD); cofactor = inorganic ion (Cl⁻, Zn²⁺). Apoenzyme (inactive) + cofactor ⇒ holoenzyme (active).
  • Describe = what you see; Explain = why. Split graphs into part 1 & part 2.