Nucleic Acids & Protein Synthesis
- ① nucleotide → polynucleotide (DNA / RNA structure)
- ② DNA replication (semi-conservative) · Meselson–Stahl
- ③ the genetic code (5 features) · ATP structure
- ④ protein synthesis: transcription → RNA processing → translation
- ⑤ gene mutations → sickle-cell anaemia
1. Nucleic Acids & the Nucleotide
Nucleic acids come in two types: DNA (deoxyribonucleic acid) and RNA (ribonucleic acid). Both are polymers — more precisely polynucleotides (poly = many; many nucleotides joined together).
Nucleotide = the monomer / basic unit of nucleic acids. DNA strand = polymer of nucleotides, RNA strand = polymer of nucleotides.
A nucleotide has 3 parts:
- Pentose sugar (5-carbon sugar)
- Nitrogenous base — adenine, thymine, cytosine, guanine, uracil
- Phosphate group (at least one)
The 2 pentoses (learnt in biological molecules): deoxyribose and ribose. A DNA nucleotide and an RNA nucleotide differ in the sugar and in one base:
bases: A, T, G, C
bases: A, U, G, C
- Ring = O + 4 carbons (C1′–C4′). There is no room in the ring for the 5th carbon → C5′ sits outside the ring.
- Base on C1′ · phosphate on C5′ · OH on C3′ (used later to make the bond).
- de-oxy = “oxygen missing”: at C2′ only, OH becomes just H. The other OH groups keep their oxygen. (Two different pentoses — not the same sugar with an O removed from everywhere.)
- Only ONE base is attached to each nucleotide — any one of the allowed four.
| Nucleotide name | Sugar | Possible bases | |
|---|---|---|---|
| in DNA | deoxyribonucleotide | deoxyribose | A · T · G · C |
| in RNA | ribonucleotide | ribose | A · U · G · C |
Uracil replaces thymine in RNA ⇒ in total 5 bases: A, T, G, C, U.
Two ways to classify the bases
① by which nucleic acid they are in (above). ② by size = number of rings:
Exam style: if a drawn nucleotide shows a double-ringed base on C1′, it is a purine (single ring ⇒ pyrimidine). Purines are larger, pyrimidines smaller.
2. Joining Nucleotides — the Phosphodiester Bond
One nucleotide = one monomer. To get a dinucleotide and then a polynucleotide, nucleotides join by condensation (a small molecule — water — is released, just like in carbohydrates, proteins, lipids).
⇒ lose H₂O ⇒ phosphodiester bond
- Phosphodiester bond = covalent = strong (strong bonds = covalent & ionic → drawn as a solid line).
- Hydrogen bonds = weak → drawn as a dotted line. (Glue analogy: weak bond = temporary glue that peels off; strong bond = permanent adhesive.)
- Every nucleotide in the chain is held to the next by one phosphodiester bond. More than 2 units ⇒ polynucleotide (e.g. 6 nucleotides = 5 bonds).
A polynucleotide = one DNA (or RNA) strand
Why is a free phosphate seen only at ONE end? The phosphate on C5′ of every other nucleotide has lost its OH in condensation — it is busy in a phosphodiester bond. Likewise the 3′-OH of every nucleotide except the last is used up.
5′ end = the end with a free (unbonded) phosphate.
3′ end = the end with a free (unbonded) OH.
Backbone: the chain of sugar + phosphate held by phosphodiester bonds = the sugar–phosphate backbone (like our spine). We do not say “deoxyribose-phosphate” because it is the same idea for DNA & RNA.
Nitrogenous bases are NOT part of the backbone and do not join nucleotides together — they stick out and later hydrogen-bond with bases of another strand.
3. Structure of DNA
Classic statement: DNA is a double-helical structure. Break it down: double = made of 2 strands; helical = spiral (braided, like a twisted rope-ladder).
- ✱ double stranded → 2 sugar–phosphate backbones (each a polynucleotide) — held together by H-bonds between bases
- ✱ helical
- ✱ antiparallel
Antiparallel: the two strands are parallel (side by side, not crossing) but run in opposite directions — one is 5′→3′, the other 3′→5′.
Complementary base pairing (like enzyme & substrate being complementary): each base pairs with one particular base only:
Getting the other strand: write the complement of each base, then reverse the direction: 5′ AAGTCGCCTA 3′ ⇒ 3′ TTCAGCGGAT 5′ (read 5′→3′ it is TAGGCGACTT).
Chargaff's rule
% A = % T and % G = % C
⇒ % purines = % pyrimidines (A + G = T + C)
Why? every A in one strand sits opposite a T in the other, every G opposite a C. So if one strand has 6 A, the partner strand has 6 T; 10 G ⇒ 10 C. Add up: the purines of the whole molecule = the pyrimidines.
Check (ma'am's random code above): purines = 3 A + 2 G = 5 in the top strand… and the pyrimidines also 5; same in the bottom strand. ✓ rule holds.
Stability of DNA — 3 reasons
- Numerous hydrogen bonds between the complementary base pairs. Each H-bond is weak, but there are so many that together they act like glue holding the 2 strands.
- Strong phosphodiester bonds (covalent) within the sugar–phosphate backbone.
- Helical structure → provides protection: enzymes cannot easily attack the DNA molecule.
Why does the helix protect? Imagine DNA as a plain linear molecule: enzymes could land anywhere and cut it. Twisted into a compact spring-like helix, only the ends are open to enzyme attack → the helix shields it from damage.
4. RNA and DNA vs RNA
RNA is of 3 types:
- mRNA messenger RNA · tRNA transfer RNA · rRNA ribosomal RNA (found in ribosomes)
- Single stranded — ALL RNA is. (tRNA looks double-stranded, but it is one strand folded back on itself.)
- Pentose = ribose · bases A U G C (U replaces T)
- Shape: linear (mRNA, rRNA) or clover-leaf (tRNA) · non-helical
- Shorter than DNA · short-lived · made by transcription
| DNA | RNA | |
|---|---|---|
| Sugar | deoxyribose | ribose |
| Bases | A T G C | A U G C |
| Strands | double stranded | single stranded |
| Shape | helical | non-helical (linear / clover leaf) |
| Size | the larger molecule | the smaller molecule |
| Lifespan | long-lived, stable | short-lived |
| Produced by | DNA replication (S phase) | transcription |
5. DNA Replication
Replication = making an exact copy of DNA. It happens in the S phase of interphase (before mitosis — this is how the amount of DNA is doubled).
Requirements:
- Parental DNA — each strand acts as a template
- Enzymes (every reaction in the body is enzyme-catalysed): DNA helicase, DNA polymerase, DNA ligase
- Energy in the form of ATP (the energy currency of the cell)
- Activated nucleotides
Activated nucleotide — why & what
- A normal (non-activated) nucleotide has just 1 phosphate — it has no extra energy (like a lazy person); not good enough for the job.
- Any process needs energy. A nucleotide is activated by adding 2 more phosphate groups (phosphorylated) → 3 phosphates. These phosphates come from ATP (the bonds between phosphates are energy-rich: when a phosphate breaks off, energy is released).
- Why activated? The new strand is built from DNA monomers = nucleotides; we don't chop the old DNA up — we synthesise from fresh nucleotides.
Replication is SEMI-CONSERVATIVE
Conserve = preserve unchanged. Semi = half. So semi-conservative = half of the parent molecule is conserved: each new (daughter) DNA = 1 parental strand + 1 newly synthesised strand.
- Helicase breaks the H-bonds → the 2 strands separate; each is now a template; bases are exposed (unbonded).
- Activated nucleotides arrive and pair by complementary base pairing (temporary H-bonds): A–T, G–C.
- Phosphodiester bonds form between neighbouring new nucleotides → new sugar–phosphate backbone.
- Finally the H-bonds between the template and the new strand hold the new helix together.
The mechanism — role of each enzyme
| Enzyme | Role |
|---|---|
| DNA helicase | unwinds & unzips the DNA by breaking H-bonds between the two strands (weak bonds → easy to break); makes 2 template strands |
| DNA polymerase | attaches (at the 3′ end of the template side) and joins complementary activated nucleotides → forms the new strand's sugar–phosphate backbone (phosphodiester bonds). Always 5′ → 3′. |
| DNA ligase | joins the Okazaki fragments on the lagging strand into one continuous strand |
Leading vs lagging: the two parental strands are antiparallel but polymerase has only one direction.
- Leading strand = continuous replication: polymerase just follows the helicase as it unzips.
- Lagging strand = discontinuous replication: here 5′→3′ means working backwards (away from the fork). Polymerase waits until helicase has opened enough, then makes a short fragment, then another … → Okazaki fragments. (It cannot change its method, so it changes its direction.)
- If both new strands were made the same way they would both be 5′→3′ and the antiparallel principle would break.
- DNA ligase then joins all the fragments → one solid strand.
- Memory: “lag” = like a lagging screen / internet — a break in continuity.
Three models of replication
- Conservative: parental DNA stays whole (both old strands together), the other daughter is wholly new.
- Semi-conservative ✓ (accepted): each daughter = 1 old + 1 new strand.
- Dispersive: each strand of both daughters is fragmented — some parts old, some new.
Meselson–Stahl experiment — how semi-conservative was proved
- Two isotopes of nitrogen: N¹⁵ = heavy, N¹⁴ = light (both non-radioactive → harmless). Nitrogen is part of DNA (in the bases!), so growth medium decides which N goes into the DNA.
- Used E. coli — it divides (one generation) every 20 minutes.
- Grew E. coli in N¹⁵ medium → all its DNA is N¹⁵ = heavy DNA = generation 0.
- Moved the bacteria to N¹⁴ medium; sampled every 20 min and checked the DNA.
- After 20 min (generation 1): ALL DNA is hybrid — one N¹⁵ strand + one N¹⁴ strand → 50 % N¹⁵ : 50 % N¹⁴.
- After 40 min (generation 2): hybrid DNA and completely light DNA. Count strands: N¹⁴ : N¹⁵ = 3 : 1 (75 % : 25 %).
- Why does N¹⁴ rise? The only N in the medium is N¹⁴, so every new strand is N¹⁴; the old N¹⁵ strands are conserved but get diluted.
| gen | % N¹⁵ | % N¹⁴ |
|---|---|---|
| 0 | 100 | 0 |
| 1 | 50 | 50 |
| 2 | 25 | 75 |
| 3 | 12.5 | 87.5 |
| 4 | 6.25 | 93.75 |
% N¹⁵ ÷ 2 each generation; % N¹⁴ = 100 − % N¹⁵.
Board slip: the notes show “1 : 8” for the later generation — it means 1 in 8 strands = 12.5 % N¹⁵ (as a ratio N¹⁵ : N¹⁴ it is 1 : 7). The middle flask also says “80 %” — it should be 50 %.
6. DNA & the Genetic Code
History: proteins were discovered before nucleic acids. Enzymes (proteins) control every life process, so scientists first assumed proteins = genetic information. Then Watson & Crick discovered DNA, and it became clear that DNA holds the genetic information; proteins carry out metabolism. So: how does DNA decide which protein to make?
Primary structure of a protein = the sequence of amino acids in a polypeptide (e.g. Met – Glu – Ala). Each protein has a unique amino-acid sequence ⇒ unique structure ⇒ unique function.
① The sequence of DNA bases must be the code for the sequence of amino acids in proteins.
② Each type of protein has a unique amino-acid sequence which determines its structure and hence its function.
③ The sequence of bases in the DNA of a cell = the code for all the proteins of that cell and organism.
(Every body cell has the same DNA as the zygote it came from. Identical twins share the same genotype — but their gene expression/phenotype can still differ.)
What exactly is a gene?
Better: a particular sequence of DNA nucleotides which codes for a polypeptide.
- The short form is acceptable for marks, but a gene is NOT the whole DNA — DNA is made of many genes.
- One gene = one complete polypeptide (insulin gene ⇒ enough nucleotides for all of insulin's amino acids).
- Gene expression = protein synthesis = when the gene successfully converts into a protein. A gene may sit dormant for years (e.g. a hormone gene switched on only at a certain age) — it was always there, just not expressed.
Note: ma'am quoted “416 amino acids” for an insulin chain but wasn't sure — real human insulin has only 51 (A chain 21 + B chain 30). The idea is what matters.
Understanding the code — 5 features
There are 20 amino acids to be coded for, but DNA has only 4 bases. Which code length works?
| bases read at a time | possible codes | enough for 20 amino acids? |
|---|---|---|
| 1 (singlet) | 4 | ✗ only 4 amino acids |
| 2 (duplet) | 4² = 4 × 4 = 16 | ✗ “cannot code for 20 amino acids” |
| 3 (triplet) | 4³ = 64 codons | ✓ 64 ≥ 20 |
(Ma'am's lists: 1 base: A, C, G, T · duplets: AA, AC, AG, AT, CA, CC, CG, CT … → 16 · triplets: AAA, ACC, AGG, ATT, ACA, AGA, ATA … → 64. Letters X, Y, Z… stood for amino acids.)
① Genetic code is a TRIPLET code
Codon = a sequence of 3 consecutive nucleotides in a DNA or RNA molecule.
The order of triplets decides the order of amino acids in the chain (triplets X, Y, A, Z ⇒ chain X – Y – A – Z). A gene of 45 bases = 15 triplets = 15 codons.
② Genetic code is DEGENERATE (redundant)
64 combinations is more than needed for 20 amino acids ⇒ 44 extra triplets ⇒ each amino acid is coded by more than one triplet.
More than one code for the same amino acid is fine; a codon for a different amino acid, or a nonsense code, would not “open the account”.
③ Genetic code is PUNCTUATED
A sentence with no full stop never ends! The ribosome needs to know where to start and stop: stop codons don't code for any amino acid — they are the “full stop”.
| STOP codons (mRNA) | mnemonic |
|---|---|
| UAA | “U are away” |
| UAG | “U are gone” |
| UGA | “U go away” |
Note: mRNA has U, no T (so “TAC” can't be mRNA; “AUG UCU CCG UAC CAC UAA” → the stop is UAA).
④ Genetic code is NON-OVERLAPPING
Adjacent bases / codons do not overlap: each base belongs to only one triplet; each triplet makes its own amino acid without interfering with its neighbour.
⑤ Genetic code is UNIVERSAL
All living organisms use similar triplet codons for the same amino acids: AUG codes for methionine in humans, rats, monkeys…. Say “similar”, not “the same” (it is true for most organisms).
- Triplet — 3 bases = 1 codon = 1 amino acid (4³ = 64)
- Degenerate — 64 − 20 = 44 extra → >1 codon per amino acid
- Punctuated — start AUG; stop UAA, UAG, UGA
- Non-overlapping — adjacent codons don't share bases
- Universal — (similar) in all organisms
7. Structure of ATP
ATP = adenosine triphosphate (A from adenosine, T = “tri”, P = phosphate).
- Adenosine = ribose (pentose) + adenine (base). Triphosphate = 3 phosphate groups (mono = 1, di = 2, tri = 3).
- So ATP = a modified nucleotide = activated nucleotide = phosphorylated nucleotide (phosphorylation = adding phosphate groups): a ribonucleotide (A) with 2 extra P groups.
- AMP (adenosine mono-phosphate, 1 P) = just a simple nucleotide; ADP = 2 P; ATP = 3 P.
- The bonds between the phosphate groups are energy-rich (energy is stored there; released when a phosphate breaks off).
8. Protein Synthesis — Overview
Protein synthesis is an active process = energy-consuming → needs ATP (ATP is the cell's energy currency — like only Pakistani rupees work in Pakistan, only ATP energy works in the cell).
Two stages (each followed by a modification):
- (i) TRANSCRIPTION — in the nucleus: synthesis of mRNA using a gene; then post-transcriptional modification (RNA processing).
- (ii) TRANSLATION — at the ribosomes: synthesis of a polypeptide using mRNA; then post-translational modification (= protein folding).
Why do we need mRNA?
- All genetic information is in the DNA, which cannot leave the nucleus; but proteins cannot be made inside the nucleus (too little space) → the information must be carried out to the cytoplasm.
- mRNA = the translator / messenger between the language of DNA and the language of protein (like an interpreter between an Urdu speaker and an English speaker).
- Only the gene needed at that moment is unzipped and expressed. If the whole DNA were transcribed, hundreds of unneeded polypeptides would be made together → protein levels rise → harmful, the cell could burst.
9. Transcription
- Site: nucleus · result: synthesis of mRNA using a gene.
- Why only one DNA strand? RNA is single stranded, so one template is enough.
- Template = a pre-existing design (like a Canva template): the strand that gets copied = template strand = transcribed strand.
Requirements:
- Activated ribonucleotides — ribo, not deoxyribo (deoxyribonucleotides would build DNA, we want RNA!); activated by ATP phosphates.
- Template strand of the gene (of the DNA) — only the gene needed, not the whole DNA.
- RNA polymerase — joins the monomers (poly-mer-ase!) = the ribonucleotides complementary to the template.
- Energy in the form of ATP
Gene structure & the 3 stages
- Promoter = start point of a gene; the site to which RNA polymerase binds for transcription.
- Terminator (transcription terminator sequence) = marks the end of transcription.
- Exons = coding part (carry a message). Introns = non-coding (no code, no message — like the appendix: present, but no role).
- H-bonds between the DNA strands break ⇒ unzipping — only the relevant gene unzips.
- One strand = the template strand.
- RNA polymerase joins activated ribonucleotides (complementary to the template) via phosphodiester bonds, in the 5′ → 3′ direction (all polymerases!).
- Before the phosphodiester backbone is made, the mRNA is held to the template by H-bonds. These are temporary: when mRNA is complete they break — mRNA must leave the nucleus and attach to a ribosome.
- The product is the primary transcript (immature mRNA): a complementary copy of the whole gene including intron sequences — not yet able to bind a ribosome.
Which strand was transcribed? The mRNA is complementary to the template: AUG… ⇒ template TAC… (the “TAC strand”). The ATG-strand is the non-transcribed one. AUG = start, UAG = one of the 3 stop codons.
10. Post-transcriptional Modification (RNA processing)
Site: nucleus. The primary transcript is modified so that it can survive in the cytoplasm and attach to a ribosome after leaving the nucleus. Also called RNA processing. 3 steps:
(1) Splicing
- Removal of introns (non-coding) and joining of exons (coding).
- Enzyme: spliceosome — a “genetic scissor”.
- Non-coding ≠ no bases. Introns are copied into the primary transcript; their base sequence just doesn't code for any amino acid.
(2) 5′ capping (3) Polyadenylation at 3′
- 5′ capping = addition of a modified guanine at the 5′ end (like putting a cap on a toothpaste tube — protects the contents).
- Polyadenylation at 3′ = poly (many) + adenylation (adenine nucleotides added): about 150–200 adenine nucleotides at the 3′ end (the poly-A tail).
- Cap + tail protect both ends from intracellular enzymes that would attack the mRNA.
- ① Removal of introns
- ② Protection of mRNA from degradation (cap + poly-A tail)
- ③ Enables mRNA to attach to ribosomes
After splicing + cap + tail: mature mRNA (the earlier primary transcript = immature / unprocessed).
11. tRNA and Ribosomes
tRNA — the amino-acid carrier
- Single stranded · bases A U G C (common to all RNA).
- Clover-leaf shaped — looks double-stranded but is ONE strand folded (5′ end and 3′ end are both on top).
- Intramolecular complementary base pairing with H-bonds between the bases — within the same molecule (A–U, G–C), which holds the fold.
- Anticodon: each tRNA has a specific anticodon, and is specific for carrying one particular amino acid. The anticodon determines which amino acid attaches to the tRNA = its “badge / ID card”. One tRNA carries one amino acid (alanine-tRNA → alanine, glycine-tRNA → glycine …).
- The amino acid attaches at the 3′ end (opposite the anticodon). The 3′ end always ends with CCA (read 5′→3′; drawn top-down as A-C-C).
e.g. codon UCA ⇒ anticodon AGU · codon AUG ⇒ anticodon UAC (Met-tRNA).
Board slip: the notes write the anticodon of UCA as “A G A” — the complement is A G U.
Drawing tRNA quickly: draw a cross; the long line is the 3′ end and the anticodon sits opposite to it.
tRNA + its amino acid = charged tRNA = aminoacyl-tRNA complex. The attachment is reversible (an enzyme is involved — details not needed): what attaches can detach.
Ribosome
- Two sub-units: a large and a small sub-unit, made of protein + rRNA (ribosomal RNA).
- The large sub-unit contains the enzyme peptidyl transferase (makes peptide bonds).
- The two sub-units assemble (ribosome assembly — possibly helped by Mg²⁺ ions) when needed and disassemble afterwards.
12. Translation
Site: ribosomes — free in the cytoplasm or on the RER.
Requirements: ① ATP ② ribosomes (the site) ③ mRNA (the molecule being translated; it left the nucleus through a nuclear pore) ④ amino acids ⑤ tRNA (carrying specific amino acids).
Divided (like transcription) into initiation → elongation → termination. The mRNA of the example has start AUG, 4 triplets in between, and a stop codon (UAG): AUG GCG GGA CUC UGC UAG.
- mRNA attaches to the small sub-unit of the ribosome.
- The start codon AUG codes for methionine, so the first tRNA (carrying Met, anticodon UAC) pairs up with it — temporary H-bonds; no peptide bond yet.
- The first amino acid of every chain is Met. (Not every finished polypeptide contains Met — it can be removed later.)
- The sequence of codons on mRNA is translated into the sequence of amino acids of the polypeptide chain.
- 2 codons / 2 tRNAs are exposed in the ribosome at one time. The enzyme peptidyl transferase (large sub-unit) forms peptide bonds between the neighbouring amino acids (covalent bonds of the primary structure).
- Once the peptide bond is made, the tRNA detaches (it was only a carrier) — codon–anticodon H-bonds are weak; the ribosome moves on to the next codon.
- Occurs when the ribosome reaches a stop codon (UAA, UAG or UGA — any one).
- The ribosome disassembles (large + small sub-unit separate) and releases the polypeptide chain into the cytoplasm.
Post-translational modification = protein folding
Takes place in the rough ER: the polypeptide enters the RER sacs. Primary structure (from translation) → secondary (α-helices, β-pleated sheets) → tertiary (R-group interactions: H-bonds, hydrophobic interactions, ionic bonds, disulfide links) → quaternary (when > 1 polypeptide chain interact).
| Transcription | Translation | |
|---|---|---|
| Where | nucleus | ribosomes (free / RER) |
| Makes | mRNA (using a gene) | polypeptide (using mRNA) |
| Enzyme | RNA polymerase | peptidyl transferase |
| Bond made | phosphodiester | peptide |
| Start / end | promoter / terminator | AUG / stop codon |
| Then | RNA processing | protein folding (RER) |
13. Gene Mutation
Mutation = a change in the genetic information (DNA = our hereditary information bank). Two kinds:
change in the base sequence in part of the DNA molecule ⇒ alteration in the sequence of nucleotides which may alter the sequence of amino acids in a polypeptide chain
3 types of gene mutation: base substitution · base addition (insertion) · base deletion.
Base substitution — a base is replaced by a different base
| Type | Definition | Why (analogy) |
|---|---|---|
| Silent | no overall change in the polypeptide chain despite gene mutation / base substitution | degenerate code: new codon codes the same amino acid |
| Missense | a mutation that changes an amino acid in a polypeptide chain | miscommunication; complete chain, same length, but wrong amino acid |
| Nonsense | a mutation that changes a codon to a stop codon, so protein synthesis (the polypeptide chain) ends abruptly | makes no sense; chain incomplete |
Base addition (insertion) & base deletion
Addition / removal of one or more nucleotides. This may lead to a FRAMESHIFT mutation. (Think photo frame: add or remove something and the frame shifts.)
Board example (codons): UAC UGG CUA GUA CAU = Tyr–Trp–Leu–Val–His. Insert one C → UAC UCG GCU AGU ACA U = Tyr–Ser–Ala–Ser–Thr: one C, and everything after it is read wrongly.
Board slip: its first line is printed “TAT TGG…” — it should be TAC TGG… for the inserted C to give the second line.
Not every insertion/deletion shifts the frame: adding or removing a multiple of 3 nucleotides (a whole triplet) keeps the frame — the code is a triplet code. Leftover 1 or 2 bases = the problem.
14. Sickle-Cell Anaemia
- An inherited (genetic) disorder caused by base substitution — a classic missense mutation.
- Homozygous recessive: the child inherits the recessive allele from both parents.
- Affects the RBCs — which are mostly haemoglobin (Hb). Hb = 4 polypeptide chains: 2 α-globin + 2 β-globin. The disorder is due to the β-globin chain (made by one gene).
| Genotype | Allele | Result |
|---|---|---|
| HbA HbA | HbA = normal / dominant | normal |
| HbA HbS | HbS = abnormal / recessive | carrier (sickle-cell trait) — no disease |
| HbS HbS | both abnormal | sickle-cell DISEASE |
What goes wrong?
- Normally the 6th triplet of the β-globin gene is CTC → glutamic acid (hydrophilic = soluble). After substitution: CAC → valine (hydrophobic = insoluble). T is replaced by A.
- The β-globin chain, so haemoglobin, becomes less soluble → precipitates (small lumps — like lumps in a flour/besan mix) inside the RBC. Lumps polymerise into long fibres which pull the RBC wall inward → sickle (crescent) shape, smaller capacity.
- RBCs have no nucleus/mitochondria so as to carry the max. of Hb and O₂ — so any loss of capacity matters a lot.
Symptoms & treatment
reduced O₂-carrying capacity of the blood ⇒
- Fatigue — less O₂ ⇒ less aerobic respiration ⇒ less ATP ⇒ tires quickly
- Swelling / pain in hands & feet
- Reduced number of RBCs (anaemia — RBCs are smaller, wear out faster)
- Frequent infections
- Stroke / heart attack — rigid sickle cells block blood vessels (obstruction → blood cannot reach tissues)
Symptoms only are controlled by: antibiotics, vaccinations (frequent infections), analgesics / painkillers (swelling & pain).
15. Full Chapter Cheat-Sheet
- Nucleotide = pentose + nitrogenous base (on C1′) + phosphate (on C5′). Deoxyribose (C2′ = H) in DNA; ribose (C2′ = OH) in RNA.
- Bases: DNA A T G C · RNA A U G C. Purines (A, G) double ring “Pure As Gold”; pyrimidines (C, U, T) single ring “CUT”.
- Condensation (C3′–OH + phosphate) → phosphodiester bond C–O–P–O–C (covalent) → sugar–phosphate backbone. 5′ end = free P; 3′ end = free OH; read 5′→3′.
- DNA: double-stranded, helical, antiparallel; A=T (2 H), G≡C (3 H); Chargaff: %A=%T, %G=%C, purines = pyrimidines.
- Stability: many H-bonds · strong phosphodiester bonds · helix (protection from enzymes).
- RNA: single stranded, ribose, AUGC, shorter, short-lived, non-helical; mRNA / tRNA / rRNA; made by transcription (DNA by replication).
- S phase; needs parental DNA, helicase / polymerase / ligase, ATP, activated nucleotides (deoxyribonucleotide + 2 P).
- Semi-conservative: each daughter = 1 old + 1 new strand. Polymerase builds 5′→3′ only → leading (continuous) / lagging (Okazaki fragments, joined by ligase).
- Meselson–Stahl: N¹⁵ → N¹⁴, E. coli, 20 min; gen 1 all hybrid (50:50), gen 2 hybrid + light (N¹⁴:N¹⁵ = 3:1); % N¹⁵ ÷ 2 each generation; lines cross at 50 % at generation 1.
- Gene = particular sequence of DNA nucleotides coding for a polypeptide; gene expression = protein synthesis.
- Code: triplet (64), degenerate (44 extra), punctuated (start AUG; stop UAA UAG UGA), non-overlapping, universal.
- ATP = ribose + adenine + 3 P = modified / activated / phosphorylated nucleotide.
- Transcription (nucleus): template strand + activated ribonucleotides + RNA polymerase + ATP; initiation (polymerase binds promoter) → elongation → termination (terminator); product = primary transcript.
- RNA processing: splicing (introns out; spliceosome) · 5′ cap (modified G) · 3′ poly-A tail (150–200 A) → mature mRNA (protection + ribosome attachment).
- tRNA: clover leaf, intramolecular H-bonds, anticodon, aa at 3′ end (CCA). Ribosome: large + small sub-unit (protein + rRNA); peptidyl transferase in large.
- Translation (ribosomes): initiation (mRNA to small sub-unit; Met-tRNA pairs with AUG) → elongation (peptide bonds) → termination (stop codon; ribosome disassembles, chain released). Polysome = many ribosomes on 1 mRNA. Then folding in RER.
- Gene mutation (random): substitution (silent / missense / nonsense), addition & deletion → may cause frameshift.
- Sickle cell: homozygous recessive HbSHbS; β-globin 6th triplet CTC→CAC; glutamic acid (hydrophilic) → valine (hydrophobic) → precipitates → fibres → sickle RBC → ↓ O₂ capacity; treatment = bone marrow transplant.