Year 12

AQA A level Physics Estimates Notes

Estimates

— Physics · AS Level (7408) · "Physical Quantities & Measurements" add-on —
★ Exam Tip: Estimates come up often, but are worth ≤ 1 mark — never a whole question. Sir: "not the end of the world" if you forget one. A full question will never depend only on an estimate. Some you must memorise; many you can work out from things you already know.

1. Memorise or Work Out?

  • Memorise (can't be derived): masses of everyday objects, densities of oil/mercury, speed of sound, speed of light in glass, hair thickness, typical slit/grating numbers, nucleus & atom size.
  • Work out (formula + a number you know): kWh → J, sphere volume, athlete's speed & KE, wavelengths in 1 m, fringe separation, frequency from λ, carbon-atom mass.
  • Papers may give an estimate you were never taught (grain of sand, coin…) → just have a rough idea of its size / mass.
Data sheets — what you get in the exam: two printed sheets come with the paper (not a separate booklet). One has constants (g, c, e …) and one has formulas. For AS only a short formula list is printed; the next sheet (A2) is full. Not every formula is given — learn the rest. Constants don't need memorising. (Chemistry gives everything; Physics does not have its own stand-alone booklet.)

2. Typical Masses

Object Estimate Sir's way to remember
Apple 200 – 250 g 1 kg of apples ≈ 5 apples (sometimes 4) ⇒ 1000÷5 = 200 g, 1000÷4 = 250 g
Protractor 5 – 10 g lighter than a coin-ish; very light
30 cm ruler ≤ 20 g heavier than protractor, but never more than 20 g
Scientific calculator 80 – 100 g memorise
Cell phone 60 – 100 g about as heavy as a calculator, never more
Coin ≈ 1 g (0.5 – 5 g) not more than ~5 g, not much less than 0.5 g
Grain / speck of sand ≈ 0.01 g definitely < 0.1 g
Typical human / athlete 60 – 80 kg (60, 80, up to ~90) — an Olympic athlete is never heavier
1 litre of water 1 kg (1000 g) 1 L = 1000 cm³ (O-level) × 1 g/cm³ ⇒ 1000 g
Carbon atom ≈ 2 × 10⁻²⁶ kg work out: 12 u × 1.66 × 10⁻²⁷ (see §7)
Sir's trick: ruler → protractor → coin: all small ⇒ stay in grams. Calculator & phone ≈ the same (tens of g).

Best way to remember 1 litre: 1 L = 1000 cm³, and water is 1 g per cm³ ⇒ 1000 cm³ → 1000 g = 1 kg. Remember 1 L = 1000 cm³ — more useful than remembering "1 kg".

3. Densities, Pressure & Speeds

Quantity Value Note
Density of water 1000 kg m⁻³ = 1 g cm⁻³ learn either form — very handy
Density of oil ≈ 800 kg m⁻³ must memorise (less than water)
Density of mercury 13 400 – 13 600 kg m⁻³ memorise
Density of air (RTP) 1.2 kg m⁻³ (≈ 1) room temperature & pressure
Speed of sound in air 330 m s⁻¹ (330 – 340) "every child knows it"
Speed of sound in water 1500 m s⁻¹ memorise
Speed of sound in metals 4000 – 5000 m s⁻¹ memorise
Speed of light in glass 2 × 10⁸ m s⁻¹ (c in vacuum = 3 × 10⁸, given)
Young modulus of metals 10¹⁰ – 10¹² Pa metals barely stretch ⇒ very high E
Order to remember (speed of sound): air 330 < water 1500 < metal 4000–5000 m/s. Solids are fastest.

Pressure under water

surface1 atm 2 atm3 atm 10 m10 m +1 atm +1 atm
pressure rises ≈ 1 atm every 10 m of water

Rule: pressure increases with depth — at each extra 10 m of water you add a fixed amount to the atmospheric pressure at the surface.

⚠ Discrepancy: in the lecture sir counted +2 atm per 10 m (1 → 3 → 5 atm). That doesn't match the physics, so the figure shows the checked value ↓

p = ρgh p = 1000 × 9.81 × 10 p ≈ 1 × 10⁵ Pa ≈ 1 atm so total at 10 m = 1 (air) + 1 (water) = 2 atm — double-check this with sir.

4. Sizes & Lengths

Object Estimate How
Diameter of a nucleus 10⁻¹⁴ – 10⁻¹⁵ m memorise
Diameter of an α-particle 10⁻¹⁴ – 10⁻¹⁵ m an α is a helium nucleus ⇒ same as nucleus
Diameter of an atom ≈ 10⁻¹⁰ m obviously bigger than the nucleus (lecture garbled: sir said 10⁻¹⁰ to 10⁻¹²)
Diameter of a hair 0.1 mm or 0.05 mm hold a hair against a ruler — it doesn't even fill 1 mm
Volume of a human head 1800 – 2500 cm³ work out: sphere with r ≈ 8 cm (§7)
Learn this: just memorise nucleus and atom sizes — don't try to link them to γ-radiation / radioactivity; sir dropped that explanation. α-particle comes free from the nucleus.

The recording is unclear on the exact atom range (10⁻¹⁰ / 10⁻¹¹ / 10⁻¹² were all said) — use ≈ 10⁻¹⁰ m, the standard value, and check it against your own sheet.

10−15 100 m nucleus / α atom ≈ 10−10 λ green 550 nm hair ≈ 10−4 head r ≈ 8 cm (log scale: each tick = ×10)
how small is small? sizes on a log (powers-of-ten) line

5. EM Waves & Visible Light

Idea: half of all the estimates are from the electromagnetic spectrum chapter — you already know the wavelengths, so find frequency from the wave equation.

v = fλ  ⇒  f = vλ   with v = c = 3 × 10⁸ m s⁻¹
Radiation / colour Wavelength Comment
Red light (vacuum) ≈ 700 nm (680 – 700) memorise what sir dictated
Green light ≈ 550 nm average of visible light
Blue / violet light ≈ 450 nm violet is very close to blue
Infrared 10⁻³ – 10⁻⁶ m already learnt in the EM-spectrum chapter
Ultraviolet 10⁻⁶ – 10⁻⁸ m (board) as sir gave it; note on longest λ ↓
Radio waves, X-rays — use the EM-spectrum values already learnt; frequency from f = c/λ
infrared 10−3 → 10−6 m visible 450–700 nm UV 10−6 → 10−8 m 10−2 10−3 10−6 10−8 λ / m
wavelength scale (log): longer ← → shorter
UV longest wavelength: sir noticed his working used the 10⁻⁸ end and said he'd fix it later. The longest wavelength is the 10⁻⁶ m end, so use that ⇒ f = 3×10⁸ ÷ 10⁻⁶ = 3 × 10¹⁴ Hz.
Infrared → f range f = c/λ f = 3×10⁸ / 10⁻³ = 3×10¹¹ Hz f = 3×10⁸ / 10⁻⁶ = 3×10¹⁴ Hz
UV (longest λ) f = c/λ f = 3×10⁸ / 10⁻⁶ f = 3×10¹⁴ Hz

How many wavelengths of visible light fit in 1 m?

blue 450 red 700 green 550 = average (nm)
use the middle colour as the average

Green is the average wavelength of visible light ⇒ number in 1 m = 1 m ÷ λgreen. Answer order: ~10⁶. Sir hasn't seen this worded in a real paper — just a possible estimate.

N = 1 mλ N = 1550 × 10⁻⁹ N ≈ 1.8 × 10⁶ ≈ 10⁶

6. Double Slit & Diffraction Grating

From the Superposition chapter — memorise these typical values:

Quantity Typical value
Slit-to-screen distance D 1 – 3 m (always metres, not cm)
Slit separation a 0.5 – 1 mm (good average)
Fringe separation x from x = λD/a, or memorise
Lines per mm on a grating 500 – 2000 per mm
x slitsa D = 1–3 m screen a ≈ 0.5–1 mm
double-slit set-up: λ, a, D, fringe spacing x

If you can't recall x: take λ = 550 nm (green average), D = 1 m, a = 0.5 mm and substitute.

x = λDa
x = λDa x = 550×10⁻⁹ × 10.5×10⁻³ x ≈ 1.1 × 10⁻³ m ≈ 1 mm
Careful with the grating units! 500–2000 lines are per mm, not per m. To convert to per metre: 1 mm = 1 × 10⁻³ m, so multiply by 10³.  500 /mm → 5×10⁵ /m;  2000 /mm → 2×10⁶ /m.

7. Work-It-Out Estimates

Rule: sir has done the working for these — don't memorise the answers, just remember which base fact to start from.

① Joules in 1 kWh

1 kW = 1000 W 1 h = 60 × 60 s = 3600 s E = 1000 × 3600 1 kWh = 3.6 × 10⁶ J

② Mass of a carbon atom

carbon-12 → 12 u m = 12 × 1.66 × 10⁻²⁷ m ≈ 1.99 × 10⁻²⁶ kg

③ Volume of a human head (cm³)

Don't memorise it: measure with a ruler — head radius ≈ 8 cm (everyone's is close; 8–10 cm). Treat the head as a sphere.

V = 43πr³ V = 43π(8)³ V ≈ 2100 cm³
Check: r = 8 cm gives ≈ 2.1 × 10³ — inside sir's 1800–2500 band. r = 10 cm would give ≈ 4.2 × 10³ (outside), so stick with r ≈ 8 cm.

④ Olympic sprinter (100 m race)

Usain Bolt's record 9.58 s → call it ≈ 10 s (others 10 – 10.5 s). Typical mass of athlete: 60 – 80 kg.

Speed v = dt v = 10010 v ≈ 10 m s⁻¹
Kinetic energy KE = 12mv² KE = ½ × 60 (to 80) × 10² KE ≈ 3000 – 4000 J
Note: sir said "½mv" in the lecture — it's of course ½mv². Mass 60 → 3000 J; mass 80 → 4000 J.

⑤ Appliances (household power)

Look at the label on a bulb: 240 V, 1 A ⇒ P = VI = 240 × 1 = 240 W. Bulbs of ~240 W or 300 W are the sort of thing sir quoted. Rough general idea only — not a precise "must-learn".

Think "scale": unfamiliar item in an exam? Compare it with something you know (coin, ruler, protractor, calculator) and give a sensible order of magnitude.

8. Don't Waste Time On These

  • Skip — "speed of light in any medium": useless, never comes.
  • Skip — refractive index of glass and of diamond ("never comes — don't know why it's listed").
  • Skip — number of particles in 1 mole: it's in the data sheet (and covered properly in A2).
  • Skip — the "wavelength of X-rays / infrared / radio" memorising: you already did these in EM spectrum.
Exam note: estimates are ≤ 1 mark each. Not knowing one is not fatal, and a whole question will never depend on one.

9. Full Cheat-Sheet

✓ Memorise-These (values)
  • Masses: apple 200–250 g · protractor 5–10 g · 30 cm ruler ≤ 20 g · calculator 80–100 g · phone 60–100 g · coin ≈ 1 g (0.5–5) · sand speck ≈ 0.01 g · human / athlete 60–80 kg · 1 L water = 1 kg (1 L = 1000 cm³)
  • Densities: water 1000 kg m⁻³ (1 g cm⁻³) · oil 800 · mercury 13 400–13 600 · air 1.2
  • Speeds: sound in air 330 (–340) · water 1500 · metals 4000–5000 m s⁻¹ · light in glass 2×10⁸ m s⁻¹
  • Sizes: nucleus & α-particle 10⁻¹⁴–10⁻¹⁵ m · atom ≈ 10⁻¹⁰ m · hair 0.1 or 0.05 mm
  • Light λ: red 700 (680) nm · green 550 nm (average) · blue/violet 450 nm · IR 10⁻³–10⁻⁶ m · UV 10⁻⁶–10⁻⁸ m
  • Waves: D (slits→screen) 1–3 m · a (slit sep.) 0.5–1 mm · grating 500–2000 lines per mm · Young modulus of metals 10¹⁰–10¹² Pa
✓ Work-Out Formulas
  • f = c/λ (c = 3×10⁸)  |  N in 1 m = 1 / λgreen ≈ 1.8×10⁶
  • 1 kWh = 1000 × 3600 = 3.6×10⁶ J  |  carbon atom = 12 × 1.66×10⁻²⁷ = 1.99×10⁻²⁶ kg
  • Head: V = 4/3 πr³ with r ≈ 8 cm ⇒ ≈ 2100 cm³  |  Sprinter: v = 100/10 = 10 m s⁻¹, KE = ½mv² ≈ 3000–4000 J
  • Fringe separation x = λD/a ≈ 550×10⁻⁹ × 1 / 0.5×10⁻³ ≈ 1 mm  |  Grating: ×10³ to convert /mm → /m
  • Pressure under water: p = ρgh ≈ 1×10⁵ Pa (≈ 1 atm) per 10 m  |  (sir counted 2 atm per 10 m — check)
★ Final Exam Tip: not on the data sheet: most formulas — so learn them. On the sheet: constants (g, c, e …). Estimates ≤ 1 mark, but some are easy marks — learn the memorise list, derive the rest.